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06 Feb 16
16:36
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08 Dec 01
Need the two values here... its been 18 years since I last looked at a quadratic equation and I cant remember where to start!
x2 - 93.568x + 2057.227632
x2 - 93.568x + 2057.227632
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You complete the square to find the formula.
I think you say that the quadratic will be of the form ax^2 +bx+c =0 Then divide throughout by a to get x^2+(b/a)x +(c/a)=0 Then X^2 +(b/a)x = -(c/a) Then complete the square on the LHS and compensate by adding the same value to the RHS Gives x^2 +(b/a)x +(b/2a)^2 = (b^2-4ac)/(4a^2), call this side Y Since the LHS is a square we can say that (x+(b/2a))^2 =Y Then x+(b/2a) = +or - the root of Y Then x= - (b/2a) +or - the root of Y So x= ( -b + or - the root of (b^2 -4ac))/ (2a) If it is correct I mill be amazed. |
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will be amazed
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Well I'm impressed anyway, Dunlaying.
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A million years ago the way i was taught was x=(-b + or - the square root of (b^2 -4ac))/ 2a. As dunlaying said.
Just plug the numbers in. |