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06 Feb 16
16:36
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Date Joined:
08 Dec 01
Need the two values here... its been 18 years since I last looked at a quadratic equation and I cant remember where to start!
x2 - 93.568x + 2057.227632
x2 - 93.568x + 2057.227632
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You complete the square to find the formula.
I think you say that the quadratic will be of the form
ax^2 +bx+c =0
Then divide throughout by a to get
x^2+(b/a)x +(c/a)=0
Then X^2 +(b/a)x = -(c/a)
Then complete the square on the LHS and compensate by adding the same value to the RHS
Gives
x^2 +(b/a)x +(b/2a)^2 = (b^2-4ac)/(4a^2), call this side Y
Since the LHS is a square we can say that
(x+(b/2a))^2 =Y
Then
x+(b/2a) = +or - the root of Y
Then
x= - (b/2a) +or - the root of Y
So x= ( -b + or - the root of (b^2 -4ac))/ (2a)
If it is correct I mill be amazed.
I think you say that the quadratic will be of the form
ax^2 +bx+c =0
Then divide throughout by a to get
x^2+(b/a)x +(c/a)=0
Then X^2 +(b/a)x = -(c/a)
Then complete the square on the LHS and compensate by adding the same value to the RHS
Gives
x^2 +(b/a)x +(b/2a)^2 = (b^2-4ac)/(4a^2), call this side Y
Since the LHS is a square we can say that
(x+(b/2a))^2 =Y
Then
x+(b/2a) = +or - the root of Y
Then
x= - (b/2a) +or - the root of Y
So x= ( -b + or - the root of (b^2 -4ac))/ (2a)
If it is correct I mill be amazed.
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