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Jones389
13 Jan 10 06:01
Joined:
Date Joined: 06 Apr 06
| Topic/replies: 4 | Blogger: Jones389's blog
I have spent hours trying to work out some odds on two figures, google has failed hopefully one of you guys can help. So the question:

if 40% of Millionaires are dyslexic
and
10 % of the public is dyslexic

how much more likely is a dyslexic person to become a millionair?
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Report DStyle • January 13, 2010 6:15 AM GMT
6 times more likely
Report Prima Donna • January 13, 2010 6:16 AM GMT
its far too early to answer things like this,im not saying I could at any time mind you.
Report Dan Chipowski • January 13, 2010 6:17 AM GMT
Not sure why anyone would even want to know the answer to that.

And what % of the public are millionaires? ;)
Report Jones389 • January 13, 2010 6:17 AM GMT
Thankyou DStyle how in gods name did you work that out
Report Jones389 • January 13, 2010 6:19 AM GMT
1% of the public become self made millionaires, the percentage of millionaires is obviously hire due to the landed gentry
Report DStyle • January 13, 2010 6:23 AM GMT
i could be wrong but lets assume the natural frequency of millionaires amongst the public is 1 in 10000.

(it doesn't actually matter what it is).

so out of our 10000 people, we have 100 millionaires and 9900 peope who aren't millionaires.

40 of those millionaires will be dyslexic, 60 wont.

1000 of the 10000 people will be dyslexic, 9000 wont.

the probability therefore of a dyslexic person being a millionaires is 40 out of 1000.

the probability of a nondyslexic person is 60 out of 9000.

the ratio is therefore 4/6*9:1
Report DStyle • January 13, 2010 6:26 AM GMT
*assume the probability is 1 in 100

as i say it doesn't matter, because the ratio between dyslexic and non dyslexic people is constant, so that proability cancels out
Report canaryboy • January 13, 2010 6:30 AM GMT
or (40/60)/(10/90)

ie the percentages
Report Jones389 • January 13, 2010 6:30 AM GMT
So based on those figures 4% of dyslexic people will be millionares?
Report V4 Vendetta • January 13, 2010 8:14 AM GMT
This is a Bayes' Theorem question. I make it:

If M is Millionaires, D is Dyslexia.

P(M|D) = P(D|M)P(M)/P(D)

= 0.4 * P(A)/0.1
= 4 * P(M)
Report Big Charlie • January 13, 2010 12:14 PM GMT
I'm rchi adn I dont gvie a kfuc wath the aneswer is
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