ODDS

(5/6)^9 = 0.194

That is the probability .^

If P=a/b then odds against are (b-a)/a.
EG P= 1/3 odds against = (3-1)/1

I make it odds of 9/5 in my head

odds against 4 appearing with 1 dice are 5/1, therefore with 9 dice 5/9

therefore odds AGAINST must be 9/5, shirley!

I ask as im am going to the casino on sunday and am doing the 6 line and if I win only once in 9 goes I will be up. so I was thinking what Is the chance  of winning or losing in this scenario?

I should let you know its single zero roulette

kenny, you`re adding the probabilities, rather than multiplying them. If you have a 5/6 and 5/6 double, you don`t get paid at 10/6.
With six dice thrown on average there should be one `four` with every throw. With more than six dice thrown, you will be getting more than one four, on average, meaning a four is more likely to appear than not to appear, making it a mathematical odds-on shot. So, it can`t be 9/5. Andriy has it right, rounded to 1.2 or 1/5

thanks timbuctooth I thought the other answers looked a little wrong

Incidentally there is no difference in these odds for one die thrown 9 times and 9 dice thrown simultaneously.

1.166666666666 x 9 equates to almost exactly 3/1

1.16 x 9 = 10.44

What has that got to do with OP's question?

Andriy is correct

0.194 = 4.15/1

^
Andriy did do a sum correctly, but didn't answer the question correctly.  Pumphol didn't even do his bizarre sum correctly.  You are the first person to actually answer the question.

The odds are 104/25 and the probability is (5/6)^9.

dave1357    20 Apr 16 13:13 
1.16 x 9 = 10.44

What has that got to do with OP's question?


Well I was doing 1.166 x 1.166 ( 9 times ) to get the 3/1
Now that may be the wrong formula  & even wrong answer  but I would have thought you would have at least seen where I was going with the 1.16 & 9 ( the nine equating to nine dice or nine throws ) so the 1.16 x 9  equating to 10.44 is not what I meant especially when I said I made it around 3/1,

so your

dave1357    20 Apr 16 14:57 
  Pumphol didn't even do his bizarre sum correctly.


My formula or lack of it was wrong but you wrote 10.44 not me, but thanks anyway for being so condescending.

so is it more or less than 80% chance a 4 would not come up = about 5-1   ?

No, it's a 19.38% chance that a 4 will not come up

0.833333⁹ = 0.833333×0.833333×0.833333×0.833333×0.833333×0.833333×0.833333×0.8333... = 0.19380600176481308

Apr 20, 2016 -- 11:52PM, pumphol. wrote:

dave1357    20 Apr 16 13:13  1.16 x 9 = 10.44What has that got to do with OP's question?Well I was doing 1.166 x 1.166 ( 9 times ) to get the 3/1 Now that may be the wrong formula  & even wrong answer  but I would have thought you would have at least seen where I was going with the 1.16 & 9 ( the nine equating to nine dice or nine throws ) so the 1.16 x 9  equating to 10.44 is not what I meant especially when I said I made it around 3/1, so your dave1357    20 Apr 16 14:57    Pumphol didn't even do his bizarre sum correctly. My formula or lack of it was wrong but you wrote 10.44 not me, but thanks anyway for being so condescending.

yvw

thanks evee that sounds like 80% a 4 would come up { is that 4-1 or 5-1

4.15/1

Surely that`s ^^^ NOT to come up?

Getting ridiculous. Are you taking the p.ss AM?
Yes, 4.15/1 that a 4 will NOT come up.

ha ha ha ha

thanks eeve. seams like about 4.15ish - 1. correct?

?

'Ow did you get on that day back in April at the casino, AM?

ist like poker, you have 54 numbers 9 number 4 so take the 9 from the 54 =45/9hence 5/1

ist like poker, you have 54 numbers 9 number 4 so take the 9 from the 54 =45/9hence 5/1

Well that clears it up