Maths Help

IF A, B & C have an equal chance of winning (and there are no other possible outcome) the chance of any of them winning once is 1/3, so the chance of any winning 5 times consecutively is (1/3)^5 = 0.0041 or 0.41%.

No idea what you mean by "AB/AC/BC winning", sorry!

By AB I mean dutching A&B so if I was to use the same logic you used for A, B & C alone would I be correct in assuming that the percentage of (2/3)^5 = 0.13116 or 13.11%

That works.

Thanks.