General Betting
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If A, B & C have an equal chance of winning what is the likelihood of A/B/C winning 5x consec and what is the likelihood of AB/AC/BC winning 5x consec...
Thanks in advance!
Thanks in advance!
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IF A, B & C have an equal chance of winning (and there are no other possible outcome) the chance of any of them winning once is 1/3, so the chance of any winning 5 times consecutively is (1/3)^5 = 0.0041 or 0.41%.
No idea what you mean by "AB/AC/BC winning", sorry! |
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By AB I mean dutching A&B so if I was to use the same logic you used for A, B & C alone would I be correct in assuming that the percentage of (2/3)^5 = 0.13116 or 13.11%
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That works.
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Thanks.
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