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hugh jardon
10 May 12 22:18
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Date Joined: 09 Oct 01
| Topic/replies: 171 | Blogger: hugh jardon's blog
12 of us are going on a golf trip to play 5 rounds of golf ( 3 groups of 4 each day)

Is it possible to arrange it that everyone plays with everyone at least once during the 5 rounds ??

I've tried for hours and cant make it work.

I'm sure it is possible, anybody got a grid
IE
1234  -   5678 -  9 10 11 12    Thats the easy part done day 1

its the next 4 days that get tricky

Thanks in advance
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Report erogenous_zone May 10, 2012 10:24 PM BST
day 2

1 2 5 6,3 4 9 10, 7 8 11 12.

day 3

1 2 7 8, 3 4 11 12, 5 6 9 10

day 4

1 2 9 10, 3 4 5 6, 7 8 11 12

day 5

1 2 11 12, 3 4 7 8, 5 6 9 10

how does that sound
Report erogenous_zone May 10, 2012 10:25 PM BST
pair them up so you have 6 pairs then 5 days playing the 5 other pairs each day
Report CaptainScarlet May 11, 2012 2:54 AM BST
You have a possible 495 different four ball combinations...so you may need to add a couple more rounds to achieve what you want to do Crazy
Report U.A. May 11, 2012 8:17 AM BST
5 and 6 never play with 11 and 12.
Report erogenous_zone May 11, 2012 11:20 AM BST
i must have duplicated 1. but it does work as you would have 6 groups of 2. and each group would play one of the other 5 groups 1 a day

day 1

1 2 3 4, 5 6 7 8, 9 10 11 12.

day 2

1 2 5 6, 3 4 9 10, 7 8 11 12.

day 3

1 2 7 8, 3 4 11 12, 5 6 9 10.

day 4

1 2 9 10, 5 6 11 12, 3 4 7 8.

day 5

1 2 11 12, 3 4 5 6, 7 8 9 10.
Report JLivermore May 11, 2012 11:22 AM BST
totally distracted me from what I was doing.

Also with eroginous's solution 7 and 8 never play with 9 and 10

At the risk of some smart arse coming up with a soltion 2 minutes after I post this:
1 - This is a very hard problem
2 - It's quite possible that there is no solution (my gut tells me there is one, but not many)

there are required 72 pairings (12*12/2). 
ER answer makes 64 pairings
I can get to 68 pairings like this:

1,2,3,4 - 5,6,7,8 - 9,10,11,12
1,4,7,10 - 2,5,8,11 - 3,6,9,12
1,5,10,11 - 2,3,6,7 - 4,8,9,12
1,2,9,12 - 3,6,8,10 - 1,5,7,11
1,4,6,8 - 3,5,9,12 - 2,7,10,11
(missing 3v11, 6v11,7v9,7v12)

I had to make a spreadsheet - DM me if you want it.
Report JLivermore May 11, 2012 11:25 AM BST
the mans a genious!

or smart arse  Laugh
Report erogenous_zone May 11, 2012 11:30 AM BST
Laugh have to agree with you though mate, very distracting!!!!! haha. its only hard if you dont pair them up isnt it, far too many combinations. once youve got your 6 pairs then its pretty simple that they play each of the other 5 pairs one a day, its just putting them in an order Cool i must have duplicated on the first one Crazy
Report donny osmond May 11, 2012 11:31 AM BST
if the solution above isnt to your liking ...

ask for "baggers" on the golf forum

he is the master of these things
Report JLivermore May 11, 2012 11:36 AM BST
yeah - really nice approach.... (golf chat).

I didn't go that way, because I felt that buy playing every day with a 'buddy', you're wasting the opportunity to play with new people.  But I think not that doesn't really matter because there are too few players.
Report erogenous_zone May 11, 2012 11:39 AM BST
yeah, would be better as a competition as well because being paired with another player you could play not only a singles tournament but a fourballs as well. as well as seeing how yourself and your pairing got on against all the other singles and pairings at the end of the week Happy
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