Forums

General Betting

There is currently 1 person viewing this thread.
hugh jardon
10 May 12 22:18
Joined:
Date Joined: 09 Oct 01
| Topic/replies: 171 | Blogger: hugh jardon's blog
12 of us are going on a golf trip to play 5 rounds of golf ( 3 groups of 4 each day)

Is it possible to arrange it that everyone plays with everyone at least once during the 5 rounds ??

I've tried for hours and cant make it work.

I'm sure it is possible, anybody got a grid
IE
1234  -   5678 -  9 10 11 12    Thats the easy part done day 1

its the next 4 days that get tricky

Thanks in advance

Post your reply

Text Format: Table: Smilies:
Forum does not support HTML
Insert Photo
Cancel
sort by:
Show
per page
Replies: 11
By:
erogenous_zone
When: 10 May 12 22:24
day 2

1 2 5 6,3 4 9 10, 7 8 11 12.

day 3

1 2 7 8, 3 4 11 12, 5 6 9 10

day 4

1 2 9 10, 3 4 5 6, 7 8 11 12

day 5

1 2 11 12, 3 4 7 8, 5 6 9 10

how does that sound
By:
erogenous_zone
When: 10 May 12 22:25
pair them up so you have 6 pairs then 5 days playing the 5 other pairs each day
By:
CaptainScarlet
When: 11 May 12 02:54
You have a possible 495 different four ball combinations...so you may need to add a couple more rounds to achieve what you want to do Crazy
By:
U.A.
When: 11 May 12 08:17
5 and 6 never play with 11 and 12.
By:
erogenous_zone
When: 11 May 12 11:20
i must have duplicated 1. but it does work as you would have 6 groups of 2. and each group would play one of the other 5 groups 1 a day

day 1

1 2 3 4, 5 6 7 8, 9 10 11 12.

day 2

1 2 5 6, 3 4 9 10, 7 8 11 12.

day 3

1 2 7 8, 3 4 11 12, 5 6 9 10.

day 4

1 2 9 10, 5 6 11 12, 3 4 7 8.

day 5

1 2 11 12, 3 4 5 6, 7 8 9 10.
By:
JLivermore
When: 11 May 12 11:22
totally distracted me from what I was doing.

Also with eroginous's solution 7 and 8 never play with 9 and 10

At the risk of some smart arse coming up with a soltion 2 minutes after I post this:
1 - This is a very hard problem
2 - It's quite possible that there is no solution (my gut tells me there is one, but not many)

there are required 72 pairings (12*12/2). 
ER answer makes 64 pairings
I can get to 68 pairings like this:

1,2,3,4 - 5,6,7,8 - 9,10,11,12
1,4,7,10 - 2,5,8,11 - 3,6,9,12
1,5,10,11 - 2,3,6,7 - 4,8,9,12
1,2,9,12 - 3,6,8,10 - 1,5,7,11
1,4,6,8 - 3,5,9,12 - 2,7,10,11
(missing 3v11, 6v11,7v9,7v12)

I had to make a spreadsheet - DM me if you want it.
By:
JLivermore
When: 11 May 12 11:25
the mans a genious!

or smart arse  Laugh
By:
erogenous_zone
When: 11 May 12 11:30
Laugh have to agree with you though mate, very distracting!!!!! haha. its only hard if you dont pair them up isnt it, far too many combinations. once youve got your 6 pairs then its pretty simple that they play each of the other 5 pairs one a day, its just putting them in an order Cool i must have duplicated on the first one Crazy
By:
donny osmond
When: 11 May 12 11:31
if the solution above isnt to your liking ...

ask for "baggers" on the golf forum

he is the master of these things
By:
JLivermore
When: 11 May 12 11:36
yeah - really nice approach.... (golf chat).

I didn't go that way, because I felt that buy playing every day with a 'buddy', you're wasting the opportunity to play with new people.  But I think not that doesn't really matter because there are too few players.
By:
erogenous_zone
When: 11 May 12 11:39
yeah, would be better as a competition as well because being paired with another player you could play not only a singles tournament but a fourballs as well. as well as seeing how yourself and your pairing got on against all the other singles and pairings at the end of the week Happy
sort by:
Show
per page

Post your reply

Text Format: Table: Smilies:
Forum does not support HTML
Insert Photo
Cancel
‹ back to topics
www.betfair.com