Imagine a gym open 18 hours a day. I go to the gym 1 hour a day, and someone I want to avoid goes 1 hour a day.
Then imagine this person to avoid is extremely irregular and can show up anytime from the first hour to the last.
Therefore, if I go everyday at the same time, 7pm, it is certain that I will see them because eventually our times will match...
Whereas if I go at a different time each day, there is only ever a 1 / 18 chance of seeing them, and I could conceivably go 6 months without running into them?
So the best strategy is a totally randomised schedule ?
Funny, found this when I searched on google. It was in a chat room:
My local gym is open 18 hours a day. I try to go around an hour a day but now this guy who moved away is back and goes to the gym around an hour a day.
Since finding out he's back, I've been varying my hours as much as possible so to avoid him.
The other night I arrived at 7 and had to leave when I saw him going in.
This is a real pain but this guy is one to avoid.
Funny, found this when I searched on google. It was in a chat room:My local gym is open 18 hours a day. I try to go around an hour a day but now this guy who moved away is back and goes to the gym around an hour a day.Since finding out he's back, I
As Trevh said, the answer to your question is that it doesn't make any difference when you go (assuming that the person to be avoided really is going at random times). Just stick to your favoured time. Of course, it's actually very unlikely that there isn't some sort of pattern to her attendance.
LMansini,As Trevh said, the answer to your question is that it doesn't make any difference when you go (assuming that the person to be avoided really is going at random times). Just stick to your favoured time. Of course, it's actually very unlikely
Gur reaction is that it wouldn't matter. But given there are fixed end points ie. opening and closing time, would this effect the analysis, since there can be no overlapping situation... unless you're assuming one can only start a session on the hour, and not go in from say 7.32 to 8.32?
Gur reaction is that it wouldn't matter. But given there are fixed end points ie. opening and closing time, would this effect the analysis, since there can be no overlapping situation... unless you're assuming one can only start a session on the hour
Go when the gym opens or 1 hour before the gym closes. This will minimize your chances of meeting this person.
Because this minimizes the potential overlap.
Mansini,Go when the gym opens or 1 hour before the gym closes. This will minimize your chances of meeting this person.Because this minimizes the potential overlap.
As others say: Odds of both scenarios are identical unless the other person wants to make sure he goes every hour, or has a shift pattern or something else that would make him rotate hours in a way that ensures he covers all hours, or there is something else about the hours, not in the question, that makes his usage 'not actually random'.
The best answer is to get over your ex boyfriend so seeing him in his sweaty muscle shirt doesn't hurt so much .
As others say: Odds of both scenarios are identical unless the other person wants to make sure he goes every hour, or has a shift pattern or something else that would make him rotate hours in a way that ensures he covers all hours, or there is someth
Zola You're definitely one of the stats expers on here, and your reply has enmboldened me to say something that was worrying me about pxb's reply earlier, which found general endorsement on here. If ( say) you divide the gym day into ( say) 8 one hour sessions. Then if both parties go on a random basis, they would have a 1/64 th chance of overlapping. If however one always go within a set 2 hr window( that either 1 hr before closing or at the opening), and the other still goes randomly, wouldn't they then have a 1/16 th of overlapping. That is it would become more likely, not less likely. Am I correct, or am I getting it hopelessly wrong, as usual ?
Zola You're definitely one of the stats expers on here, and your reply has enmboldened me to say something that was worrying me about pxb's reply earlier, which found general endorsement on here.If ( say) you divide the gym day into ( say) 8 one hour
Got that perfumed gel in your hair yet for your hot date tonight ? Also slip a tube of it into your pocket for the planned action later. Also, don't forget to stack your wallet with you know what ? And whatever you do, don't go near the gym tonight.
Got that perfumed gel in your hair yet for your hot date tonight ? Also slip a tube of it into your pocket for the planned action later.Also, don't forget to stack your wallet with you know what ?And whatever you do, don't go near the gym tonight.
remember when u were terrified of those girls in mexico? u gotta relax more im a pro
2 years ago it could have happened, now, no chance
always so paranoid frogremember when u were terrified of those girls in mexico? u gotta relax moreim a pro2 years ago it could have happened, now, no chance
Let me just say that I would think that I have pulled a few more chicks than you have so far. Of course I cheated a bit on that, by living in Thailand for a number of years, pre-AIDS.
Let me just say that I would think that I have pulled a few more chicks than you have so far.Of course I cheated a bit on that, by living in Thailand for a number of years, pre-AIDS.
"if they are truely independent events then it is better if you randomise your entry." - Why?
Isn't this thread just a classic example of the "last weekends lottery numbers make this weekends more/less likely" misconceception that people who've never studied proability come up with, except transferred to hours?
"if they are truely independent events then it is better if you randomise your entry." - Why?Isn't this thread just a classic example of the "last weekends lottery numbers make this weekends more/less likely" misconceception that people who've never
say he goes every day at 1pm. the probability of him being there at 1pm is p1=1. the probability of her being there at 1pm is p2
just checking, is he better randomising his time?say he goes every day at 1pm.the probability of him being there at 1pm is p1=1.the probability of her being there at 1pm is p2
say he goes every day at 1pm. the probability of him being there at 1pm is p1=1. the probability of them both being there is p1 x p2 = p2
just checking, is he better randomising his time?say he goes every day at 1pm.the probability of him being there at 1pm is p1=1.the probability of them both being there is p1 x p2 = p2
say he randomises the time the probability of him being there at 1pm (or any other time) is p1 is less than 1. the probability of them both being there is p1 x p2 is less than p2
say he randomises the timethe probability of him being there at 1pm (or any other time) is p1 is less than 1.the probability of them both being there is p1 x p2 is less than p2
To simplify matters, suppose that X and Y can only attend from the start of one hour to the end of that hour (and there are 18 hours).
If X goes at 1pm everyday, the probability of meeting Y is 1/18. If X goes at a random hour, the probability of meeting Y is still just 1/18 (if his hour had been 7am, then there was a 1/18 chance that she would have turned up at 7, if his had been 8am, there was also 1/18 chance that she would have turned up at 8, etc.).
Zola,That's not true.To simplify matters, suppose that X and Y can only attend from the start of one hour to the end of that hour (and there are 18 hours). If X goes at 1pm everyday, the probability of meeting Y is 1/18.If X goes at a random hour, th
"Whats the probability of meeting her given I am already there"... which is similar and not the same as "whats the probability of meeting her".
Thats a conditional statement."Whats the probability of meeting her given I am already there"... which is similar and not the same as "whats the probability of meeting her".
The original question is: is he more likely to bump into her if he goes at the same time, or he goes at different times.
I was merely stating that if he goes at the same time, there is a 1/18 chance, and if he goes at different times, whatever time that may be, there will still be a 1/18 chance.
I would have thought that this is pretty obvious. It's exactly like a game where LMansini has to get a different number, picked from 18, than his woman. Suppose each time she throws an 18-sided die. He can either pick the same number and stick to it (in which case, each throw (or gym attendance) there is a 1/18 chance of getting the same number), or he can also roll the die to get his number. Whatever number he rolls, there is a 1/18 chance that it is the same as his woman's.
The original question is: is he more likely to bump into her if he goes at the same time, or he goes at different times.I was merely stating that if he goes at the same time, there is a 1/18 chance, and if he goes at different times, whatever time th
Contrarian if it IS truely random, we are surely correct here?
IF the hours are truely random, then the hour chosen on a given day does not matter. They are just possible events, and the fact they are hours, IF I understand this question correctly, doesn't matter. It's THIS probability chestnut that some people can't seem to get their head around, same as how some people do NOT understand why 1,2,3,4,5,6 isn't less likely than any other series in the lottery, and why last weeks lottery numbers don't make this weeks less likely etc, etc.
Contrarian if it IS truely random, we are surely correct here?IF the hours are truely random, then the hour chosen on a given day does not matter. They are just possible events, and the fact they are hours, IF I understand this question correctly, do