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Sorry, odds are 5 8 & 13
Dutched price is 2.49 |
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Assuming the numbers 5,8 and 13 are in cells A1,A2,and A3 then
=1/(1/A1+1/A2+1/A3) gives you the answer |
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Thanks for the reply bongo but as I said I know how to get that answer, it's the stake that I need to work out so that if I put £33.44 on H1 and £20.90 on H2 and £12.86 on H3 then my total liability on all three is £100 - it's getting those wages that I am struggling on
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I worked it out! it doesn't look good but it goes like this
if Cell L5=5 Cell L6=8 Cell L7=13 Then =100/(((100+(100/(L6/L5))+((100/(L6/L5))/(L7/L6)))*(1/(1/L5+1/L6+1/L7)-1))/100) gives me £33.440514 to lay on the first Horse I can work out the other stakes from there. But if anyone else can make it easier I would appreciate it |
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If x, y and z are the odds....
then... b = 100xz/(z((x-1)(y-1)-1)-xy) |
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I guess a and c follow symmetrically
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ie. numerators are a=100yz... and c =100xy... (denominator the same)
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Thanks Bayes
That did the trick cheers |