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My my daughter needs to know how to work this math out.in a photograph the heights of 3 girls are 10cm, 9cm, and 7cm. The scale of the photo is 1:16 ,What is the real height of the tallest girl answer in metres.
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Tallest Girl in Photo = 10 cm
Multiply by Scale of Photo = 16 ... so real height is 10 x 16 = 160 cm How can you not crack this poser is a mystery, I must say. |
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i.e. 1.6 metres
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5.24934383 feet
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1:16 is imperial so you will have to convert it to metric to work with cm, hth
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Yes but is the 10cm girl wearing shoes with bigger heels than the other two girls?
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or one on a step
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or 7cm girl standing in a pothole.
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or in the distance.
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Primary school maths is a bitch!!
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Trawling surely.
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You'd have to know the distance to the camera, that scale would only be correct at one specific distance.
But I doubt it's that technical for kids! |
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is it the ISIS girls ?
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scale 1:16
she could be 10/16 of a cm tall |
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I cannot believe how insensitively this gentleman has been treated on here. He was clearly brought up on imperial measurement and is struggling, as many of us older ones do, with getting the decimal point correctly placed when factoring up these minor decimal metrics. It is clear that the tallest young lady is almost exactly 52ft high. Hope this helps.
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There was an documentary a couple of years ago about how in ww2 they could work out the height of V2 rockets by looking at the shadow on aerial photos, knowing the angle the sun would be at that time of day and doing the maths. Get the kids working on that
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1.6 metres
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Ebulgery - Nice one Einstein!! You should be somewhere else.
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Blackbarn
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It is hardly difficult
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That was to your 22:44 post btw.
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Capt__F 23 Mar 15 22:10
is it the ISIS girls ? ISO girls shirley? |
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Forgive me Ebulgery, but I think that might be the central point of several posts on here ahead of yours. Still, if it makes you happy.
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Thanks Mikael. Noted!
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Just Checking • March 23, 2015 10:44 PM GMT
There was an documentary a couple of years ago about how in ww2 they could work out the height of V2 rockets by looking at the shadow on aerial photos, knowing the angle the sun would be at that time of day and doing the maths. Get the kids working on that Laugh. incredibly simple as well |
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Ebulgery - not quite on the same scale as multiplying 10cm by 16, but again if it keeps you happy, stick with it.
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I spent a lot of time solving that...I thought I was clever
oh well |
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It was not just 16 X 10
you forgot the division by 100...immensely tricky |
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Ebulgery. It's not all simple, really. It's not a simple matter of a bit of trig. The problem is that you don't know the actual length of the shadow either. The apparent size of the shadow depends upon the camera specifics and the altitude of the aircraft carrying the camera.
One thing they used to look for, specifically, was cricket pitches. You could easily detect the wicket zones which were always 22yds apart and so they could scale things directly. I didn't know that the Germans even played cricket!  |
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I was assuming the plane had an altitude meter, it knows it's own height above the ground, the angle of the sun
from that the length of the shadow can be deduced and thus height of rocket, basic trig still I thought I was being clever get the answer to the OP problem |
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Actually I am not so sure about that now Naydam, the shadow, a long time since I was at school
I will think about it later, more important stuff, now this afternoon's greyhounds |
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You need the altitude, the geographical location, the camera characteristics (focal length, I think), the time of day and the apparent length of the shadow. Oh, and a pencil and a bit of paper!
AND those Log tables that you threw out years ago!  |
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I will take back my remark about it being incredible simple
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Were the 3 girls straight A students?
And if they weren't all in a straight line as well, then it affects the answer, because it's a lot more difficult. You need to know Pythagoras like the back of you hand to work it out properly, or do like I do when selecting a lay bet, take Pi as being 22/7 (and don't worry about the square root of -1 ... ignore it for the purposes of this question). |
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If the girls WERE in a straight line...that would complicate matters severely. Much easier if they are positioned in an arc.
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Noah's Arc
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Blackbarn.
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