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Vatour
01 Sep 14 14:35
Joined:
Date Joined: 22 Mar 14
| Topic/replies: 162 | Blogger: Vatour's blog
One day, it takes p hours for q factory workers to construct r items. The following day, three more workers join the team and four more items are required to be constructed.

(i)    Find how many hours it will take, in terms of p, q and r.
(ii)    If in fact it takes the same length of time, find an equation and show that it reduces to 4q=3r.
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Report PatraTheCat • September 1, 2014 2:47 PM BST
Hours required on second day = p' will be hours (p) worked on first day multiplied by the factor given by the extra workers {(q+3/q)} but divided by the factor given by the extra items that need to be made {(r+4)/r)}.

Therefore p'=p{(q+3)/q)}{r/(r+4)}

If p'=p:

1=1{(q+3)/q)}{r/(r+4)}

So {(q+3)/q}{r/{+4)}=1

So 1+(3/q)=1+(4/r)

So 4q=3r
Report Dotchinite • September 1, 2014 2:47 PM BST
The answer is 42
Report Ken Masters • September 1, 2014 2:49 PM BST
Not another PQ thread, some people never give up hope.
Report call me a taxi • September 1, 2014 3:26 PM BST
qpr are rubbish anyway.
Report Vatour • September 1, 2014 3:53 PM BST
Nice one Patra!
Report Vatour • September 1, 2014 4:11 PM BST
Patra, how does the first part become the answer?

So 1+(3/q)=1+(4/r)

So 4q=3r
Report PatraTheCat • September 1, 2014 6:33 PM BST
Subtract 1 from both sides.

3/q=4/r

Then multiply the equation by rq.
Report zorrostrikes • September 1, 2014 6:37 PM BST
sp=az
Report Just Checking • September 1, 2014 6:44 PM BST
S.P.Q.R = Senatus Populusque Romanus.

If you don't believe me, ROMANES EUNT DOMUS.
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