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One day, it takes p hours for q factory workers to construct r items. The following day, three more workers join the team and four more items are required to be constructed.
(i) Find how many hours it will take, in terms of p, q and r.
(ii) If in fact it takes the same length of time, find an equation and show that it reduces to 4q=3r.
(i) Find how many hours it will take, in terms of p, q and r.
(ii) If in fact it takes the same length of time, find an equation and show that it reduces to 4q=3r.
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Hours required on second day = p' will be hours (p) worked on first day multiplied by the factor given by the extra workers {(q+3/q)} but divided by the factor given by the extra items that need to be made {(r+4)/r)}.
Therefore p'=p{(q+3)/q)}{r/(r+4)} If p'=p: 1=1{(q+3)/q)}{r/(r+4)} So {(q+3)/q}{r/{+4)}=1 So 1+(3/q)=1+(4/r) So 4q=3r |
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The answer is 42
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Not another PQ thread, some people never give up hope.
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qpr are rubbish anyway.
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Nice one Patra!
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Patra, how does the first part become the answer?
So 1+(3/q)=1+(4/r) So 4q=3r |
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Subtract 1 from both sides.
3/q=4/r Then multiply the equation by rq. |
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sp=az
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S.P.Q.R = Senatus Populusque Romanus.
If you don't believe me, ROMANES EUNT DOMUS. |