I cant do this maths question

My instinct says its 30%?

I always keep my balls in my bag.

I go with 45%

if it's only 5 balls

10/1 for any 1 number
5/1 for any 2

62.22222%

sorry neither would be 1/10 and 1/5

oh FFS if I would read the question correct.

exactly one in three

My NAP answer.

1/3 exactly if i'm not mistaken.


8/10 * 7/9 * 6/8 * 5/7

First ball drawn not 1 of 2 ..... 8/10

A start...

Here's my Rachel Riley style breakdown.

The probability of 1st ball drawn not being one of the numbers is 80%

The probability of 2nd ball drawn not being one of the numbers is 77.77%

The probability of 3rd ball drawn not being one of the numbers is 75%

The probability of 4th ball drawn not being one of the numbers is 71.42%

That's based on drawing the balls one at a time, and the percentages are based on drawing
from the balls left in the bag NOT from 10 balls.

71.42% x 75% x 77.77% x 80%
= 0.33333%
i.e. probabilty of one in three.

try again Journey - first ball one is unwanted, NINE are wanted

nice one Journeyman

Try again Ivor - you can't fkn read :D

oh fook - read the question Ifor :(

NP Sterile. You can put your house on those figures.

yes it's 1/3 - as they said hours ago :)