If order doesn't matter I'd be inclined to think that as odds of any individual number being drawn out in first 6 is evens, its a 6 runner acca all at Evens, ie 63/1. Can't be that simple tho, can it?
If order doesn't matter I'd be inclined to think that as odds of any individual number being drawn out in first 6 is evens, its a 6 runner acca all at Evens, ie 63/1. Can't be that simple tho, can it?
if your question is supposed to work like a lottery the answer is :
12!/ 6!6!
n!/ r! (n-r)!where: n is the number of ballsr is the number of balls to be pickedso the lottery would be calculated like this:49!/ 6! (49-6)!if your question is supposed to work like a lottery the answer is :12!/ 6!6!