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a 1.36 shot would be like evens for 2-0 and 2/1 for 3-0... no idea about other prices. Thats just easy to remember
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match odds imply odds on winning single set, e.g. set odds of 1.3 lead to match odds of 1.156 (bo3) and 1.092 (bo5), 1.5--> 1.35 and 1.266, calculation has to be done with binomial distribution. Watching in play you have to think if what has happened so far changed odds of winning a set from pre match.
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assuming an equal probability of winning a single set.
bo3: P(match) = P(set)^2 + 2* (P(set)^2 * (1-P(set)) bo5: P(match) = P(set)^3 + (3* (P(set)^3 * (1-P(set))) + (5 * (P(set)^3 * (1-P(set))^2)) |
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thanks guys
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