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deadheat rules
divide by number of players tied 5th |
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cheers moneyx....found it eventually in the rules. was some free money up on the Top 5 for Tswhane open there. missed out though as found the rules too late.
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what about players tied on 4th, same?
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yep same. see below from betfair rules.
ssume there is an outright winner in a golf tournament but 7 players tie for 2nd place. In the "top 5 finish" market, after settling on the outright winner in the top 5 market there would be 4 other designated winners places available. 'Client A' has backed one of the winners for 300 at the traded price of 4.0 and 'Client B' has taken the other side of this bet. When the event is settled, the stake (300) is multiplied by 4/7 (i.e. the number of expected winners (4) divided by the number of actual winners (7)) to calculate the reduced stake (171.43) and the remainder given to the layer (128.57). The backer then receives the traded price matched (4.0) multiplied by the reduced stake (4 x 171.43 = 685.72). In this example, Client A's net winnings are 385.72 (685.72 payout minus the original 300 stake), and Client B's net losses are 385.72. |
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two tied 4th no deadheat rules
three or more tied 4th deadheat rules apply |
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Always apply to over 5 players what ever position
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thx, dam!
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If u hav Westwood top5 Honda your praying he birdies 18th
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6 players tied 5th
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