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Judge Roughneck
23 Oct 12 14:59
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Date Joined: 14 Aug 07
| Topic/replies: 105 | Blogger: Judge Roughneck's blog
If you had a system that was returning 54% winners on even money chances, how many trials would make it statistically likely to be a true edge?

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Replies: 20
By:
steeringjobnap
When: 23 Oct 12 15:25
I would want to see several thousand trials.

Although, the sample mean of the sampling distribution is approximately equal to the mean of the sampled population for all n >=30

The approximation tightens as the sample size increases.
By:
JLivermore
When: 23 Oct 12 15:28
I tried a new (to me) method for this (Bayes), I think you can say:

After 264 trials (138wins/118losses) you can be 90% sure that your edge is positive (ie true strike rate >50%).
After 422 trials you can be 95% sure that your edge is positive (ie true strike rate >50%).

Also, out of interest:
After 1022 trials you can be 90% sure that your edge is true strike rate >52%.
After 1684 trials you can be 95% sure that your edge is true strike rate >52%.
By:
Judge Roughneck
When: 23 Oct 12 15:30
Okay, i've been trying to do a bit more working out. I make it that 100 trials gives the probability of the success continuing as 82%, after 250 trials 91%, 500 - 97 and 1000 - 99%.

Does that sound right?
By:
Judge Roughneck
When: 23 Oct 12 15:31
Doh! bit slow there!
By:
Judge Roughneck
When: 23 Oct 12 15:35
Interesting, we have come at it slightly differently but the figures seem roughly similar.
By:
steeringjobnap
When: 23 Oct 12 15:37
JLivermore,

Can you post the Bayes' formula used? It's been 9 years since I've seen one!

I always thought the best way to trial such an edge's significance was to calculate the p-value [p < 0.01]
By:
Judge Roughneck
When: 23 Oct 12 15:37
Steeringjob - do you really think it needs thousands of trials to be confident?

Also, can you explain the following in simpleton termsBlush as I don't really understand!

Although, the sample mean of the sampling distribution is approximately equal to the mean of the sampled population for all n >=30
By:
steeringjobnap
When: 23 Oct 12 15:37
^ Bayesian formula even
By:
steeringjobnap
When: 23 Oct 12 15:41
I asked a Ph.D statistican the sample size required forany such type of experiement - and the answer was "5,000 trials".

It tallies with JL's analysis above i.e. the level of significance increases as the number of trials rises.

What my comment means is this:-

- take the average answer from a sample of trials [i.e.at least 30
   bets];
- the trials should be taken from the phenomenon you are looking to
   model [i.e. your edge];
- the average answer for your trials will approximate the average answer for the phenomenon as a whole;
- the scope for error falls as the number of trials rise
By:
JLivermore
When: 23 Oct 12 15:59
I used an Beta distribution, which I *think* is the distribution of the Bayesian posterior.

So for the probability your strike rate is > 50%:
=1-BETA.DIST(0.5,
By:
steeringjobnap
When: 23 Oct 12 16:01
ty - yes, that tallies.
By:
Judge Roughneck
When: 23 Oct 12 16:01
Okay, I'm not sure I get that. When you say take the average answer from a sample of trials [i.e.at least 30
   bets];
are you saying, to take average answers from trial runs of the system over different numbers of sample bets?Crazy

Also, when you say - I always thought the best way to trial such an edge's significance was to calculate the p-value [p < 0.01]
are you saying to calculate the number of trials until there is a
By:
JLivermore
When: 23 Oct 12 16:03
it didn't print all my formula - here is what I meant:

=1-BETA.DIST(0.5, number of wins, number of losers, TRUE)
By:
Judge Roughneck
When: 23 Oct 12 16:03
Not sure what happened there, half my post disappeared.

Okay, I'm not sure I get that. When you say take the average answer from a sample of trials [i.e.at least 30
   bets]; are you saying, to take average answers from trial runs of the system over different numbers of sample bets?Crazy

Also, when you say - I always thought the best way to trial such an edge's significance was to calculate the p-value [p < 0.01]
are you saying to calculate the number of trials until there is a
By:
Judge Roughneck
When: 23 Oct 12 16:04
It did it again!!
By:
Judge Roughneck
When: 23 Oct 12 16:06
If you are saying to calculate the figure so that the chances of the true figure being less is
By:
Judge Roughneck
When: 23 Oct 12 16:07
If you are saying to calculate the figure so that the chances of the true figure being less is smaller than 1%  then I calculate that number to be 839Crazy
By:
Judge Roughneck
When: 23 Oct 12 18:11
got called away from  my desk............

Thanks for the earlier replies, i'm still not really sur of a number I shoul aim for though.

What complicates the matter is that the system only throws up a bet approx 2-3 times a week and there is no way to back-test it prior to March this year so waiting for meaningful stats could be a long time!!!
By:
JLivermore
When: 23 Oct 12 18:39
statistical significance can be a pretty high bar.

If I was you I would bet it with my uncertainty about the edge taken into account and track the edge as you get more bets.
By:
FINE AS FROG HAIR
When: 23 Oct 12 19:15
Judge R
You say " What complicates the matter-----only throws up a bet 2-3 times a week-----so waiting for meaningful stats could be a long time ".
Now I'm no statistician, but couldn't you therefore just keep tracking all future events  and if they ( being those that do not throw up bets) keep running at a flat stake bet loss ( as they must do if the ones that throw up a bet strike at 52% rate), then your system is still theoretically intact, despite not getting any actual bets for the period concerned.
Or is that false logic ?
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