General Betting
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If a league of 20 teams play each other twice per season, how many league games will be played in the season?
what is the formula for any league given the number of times each team play each other and the number of teams in the league.
thanks
what is the formula for any league given the number of times each team play each other and the number of teams in the league.
thanks
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dunno if im caught here or not but each team plays 38 games. 20 teams in league play 38 games each. 20 x 38 gives you your answer
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The formula is ( number_of_teams_in_league -1 ) * number_of_times_they_play_each_other.
So - 20 teams playing each other twice is ( 20 - 1) * 2 = 19 * 2 = 38 |
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um answer is 380
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((total teams-1)*2)*(total teams/2)
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Why do you need a formula when commom sense will do it for you :
They all will play 38 matches. Multiply that with 20 teams and divide the answer by two , because there are two teams in each match. |
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Oops - my mistake. I read the question as "how many matches will each team play" , not "how many matches are there in the complete season"
Eddie - You're contradicting yourself a little there. It is only common sense because there is a formula (ie a way of working it out) |
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Of course there are a formula. All math problems with a solution will have some sort of formula to solve it , but I can assure you they can not all be solved from common sense only.
This problem though , should imo be solved by most adults that has completed elementary school. |
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the formula for working out the number of possible combinations (r) in a set (n) is
n!/(r!(n-r!)) in your case, n = 20 (size of the league), and r = 2(number of teams in a match). so the answer is 20*19/2 = 190 as they play twice, home away, we have to double it to give us the answer 380. |
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alternatively you can just use the formula the permutations (as order is relevant when considering home and away) which is
n!/(n-r)! which is 19*20 = 380 |