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Selections not locations ffs
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The reason I want to work it out is cause I think I’m being offered an overly generous cash out due to their inflated idea of what I could potentially win and may take advantage
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Should you not just be filling the calculators in for two L15s, each with the three winners to date and then each with one of the other two remaining selections? Not sure where/why you're bringing L31 into it if you can only have 4 winning selections?
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3*2*1*1
only 2 poss out comes left patent up already put two out comes in plus already won pretty easy i say 75% of best outcome trade |
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Latalomne no, as when the bet was placed there was a possibility of 5 winners, so doing lucky 15s would not give an accurate amount of bets/combinations therefore the payouts would be incorrect.
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how many games ?
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Capt would there not be an easier way work it out instead of adding up all the payouts of each individual bets? There’s 124 total combinations, there’s still a lot of math to do when working out what’s still running!
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5 games.
Game 1- 2 selections one winner (one loser obv) Game 2- 1 loser Game 3- 1 winner Game 4- 1 winner Game 5- 2 selections still to run. |
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You can still only have a L15's worth of winners if you've had a loser.... The combinations you placed are irrelevant for calculation of return. You can still only have 15 winning lines.
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Actually yeah that makes sense, for some reason I’m still thinking that the possibility of doubles and trebles involving a loser were sill in the run
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LOL, I was just about to post that I was coming around to your way of thinking!
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Wait actually it still wouldn’t be right, for example- the current 2 single selections that are winners Would still be winning doubles and singles in the current “lucky15’s” we’ll call them that wouldn’t be taken into consideration with the workings of the 2 lucky 15’s you’re suggesting....I think
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Assume bet #1 = winning selection of game 1. #2 = losing selection of game 1.... #3 = losing selection of game 2.... #4 = winning selection of game 3.... #5 = winning selection of game 4.... #6 + #7 = possible winning selections of game 5
Possible winning 4-folds are bets #1456 OR 1457 Possible winning trebles are 145 (already won) AND 146 or 147, 156 or 157, 456 or 457 Possible winning doubles are 14, 15 (both already won), 16 OR 17, 45 (already won), 46 OR 47, 56 OR 57 Possible winning singles are 1, 4, 5 (all already won), 6 OR 7. Max 15 winning bets. |
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The only thing I can't get my head around is whether you have multiple instances of some of them because of the combinations....?
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I think you do. Just don't ask me how many!
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Like I said, my brains been fried over this all day
anyway I’m being offered £1100 cash out as their possible returns show (an impossible) £7000. I worked out that as it stands I’ve won £300, though looking at either £3000 or £3800 if either of the last ones came in. But I know those figures aren’t entirely accurate so I’m lost with what to do ![]() |
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Prior to seeing the above, I was at if #6 OR #7 win, you're in for 4x L15s.... But I'm not sure that tallies with your numbers above....
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Yeah those figures were worked out at the beginning of this whole mindfunk, I think it was based on 2 lucky 15...though I’ve done that many calculations since that I have no idea. Ive also got separate trebles and 4 folds running on the same selections, least they were a bit easier to work out! The last game runs at 8.30am tomorrow and I’m not spending another minute on this. Cheers anyway
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GL with it anyway! Hope you win and we get to find out the right way! ![]() |
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https://www.aceodds.com/bet-calculator/lucky-15.html
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What would it cost you to back the two remaining possibilities on here for payouts of £3000 and £3800 (or dutch for £3800 if you're a little greedy)?
If that is less than £800 (the £1100 cashout offer minus the £300 you have already won), then the offer is over-generous. Take it and run or take it, back the remaining selections as above and all the change over £300 you have left is free money you would not have had were you to leave the bet to run. |