Football
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23 Nov 17
11:44
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20 Oct 02
Alison's cinema has 100 seats.one day it is full and she has taken £100. Prices are ,adults £3.50,,pensioners £1.00,,kids £.085.not everyone is a pensioner.how many adults ,kids and pensioners are present.?
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3 adults, 50 kids, 47 pensioners
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Must have been a good film
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100 Pensioners no adults and no kids.
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Assuming that there x Adults, y Pensioners and z Children, we get two equations:
(1) x + y + z = 100, and (2) 350x + 100y + 85z = 10000 on converting pounds to pence. Now divide second equation by 5 to get: 70x + 20y + 17z = 2000 and multiply first equation with 20 to get: 20x + 20y + 20z = 2000 On subtracting, we get 50x - 3z = 0 As Adults, Pensioners and Children can be whole number and all audience are not pensioners. So, x or z need to be greater than zero. Therefore x=3 and z =50 and y = 47 https://wild.maths.org/going-cinema |
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Sorry just read question again.
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no point in converting to pence, leave as £, that way you can immediately subtract the 2 equations to leave the adult/kid ratio
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Not everyone is a pensioner could mean that 100 people paid pensioner rates but some of them were adults that chanced getting OAP rates and didn't get asked for ID
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8 and a half pence ?
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Llemedos does not you table show £100.45??
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Sorry you are correct didnt realise you switched y & z
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not everyone is a pensioner.how many adults ,kids and pensioners are present.?
Poorly worded question. Why does there have to be any kids? If 0 kids its easy. |
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3 adults = £10.5
50 kids =£42.5 47 pensioners = £47 100 people 100 pound |
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Why does there have to be any kids?
If 0 kids its easy. No solution if no kids. |