So it's like the national lottery. To predict two consecutive cards is going to be massive odds especially in draw order. Isn't one card in any order something like 14 million to 1? In draw order, you would have to multiply that by (I think) six factorial. So for two consecutive cards in order it would be that number (14million x 6 factorial) squared divided by 2. Adding in the extra number 9 you would multiply again by 43 squared. It's a long time since I studied stats so I'm very rusty. If any statisticians could give their opinion I would be obliged.
So it's like the national lottery. To predict two consecutive cards is going to be massive odds especially in draw order. Isn't one card in any order something like 14 million to 1? In draw order, you would have to multiply that by (I think) six fact
From first principles ((49!/42!)^2)/2 = 9.37 x 10^22 Which is more or less the same answer as I got by the circuitous "National Lottery estimate" route.
From first principles ((49!/42!)^2)/2 = 9.37 x 10^22 Which is more or less the same answer as I got by the circuitous "National Lottery estimate" route.
I'd normally call bollocks on these "omg what are the chances of that" posts, but when you move in to the 8 billion to one range it becomes far more likely that there's been a ****-up of some kind. Like if you bet on black 20 times in a row and red came up every time - is it now more likely the game is ****?
I'd normally call bollocks on these "omg what are the chances of that" posts, but when you move in to the 8 billion to one range it becomes far more likely that there's been a ****-up of some kind. Like if you bet on black 20 times in a row and red
Dave I was in Vegas a few years ago and 17 came up 6 times in a row. I can't be bothered to work out the odds of that happening but it must be astronomical.
Dave I was in Vegas a few years ago and 17 came up 6 times in a row. I can't be bothered to work out the odds of that happening but it must be astronomical.
no kenny the first 17 could have been any number, ie the event was a number coming up 6 times in a row, so any number probability 1 repeating once odds 37-1 (2 zeroes in vegas) etc.
So its ~79 million to one 38^5.
Funnily enough there's another vegas story that illustrates my point. Someone won a multi-million dollar keno jackpot where I think you have to get something redic like 15 numbers from 20 drawn from 1-80. It was so unlikely that they investigated everyone involved and quickly discovered insider collusion.
I know weird things happen, but I still think that in the case of these 49s numbers the probability of some sort of glitch is much larger that the event occuring at random.
no kenny the first 17 could have been any number, ie the event was a number coming up 6 times in a row, so any number probability 1 repeating once odds 37-1 (2 zeroes in vegas) etc. So its ~79 million to one 38^5. Funnily enough there's another vega
don't know how it works studyform - is it a strict and open as the nat lotto? My only point really is when something occurs that as unusual as this, it's worth a look at the procedure.
don't know how it works studyform - is it a strict and open as the nat lotto? My only point really is when something occurs that as unusual as this, it's worth a look at the procedure.
Dave I was in Vegas a few years ago and 17 came up 6 times in a row. I can't be bothered to work out the odds of that happening but it must be astronomical.
Dave I was in Vegas a few years ago and 17 came up 6 times in a row. I can't be bothered to work out the odds of that happening but it must be astronomical.
I don't do the 47s because I don't know which balls are non triers and I am sure the draw affects the result. I remember being in a casino when 0 came up in 3 out of 5 spins. All the systems players were wiped out and a little old lady who put her 50p chips on 0 and 3 thought she was in heaven.
I don't do the 47s because I don't know which balls are non triers and I am sure the draw affects the result. I remember being in a casino when 0 came up in 3 out of 5 spins. All the systems players were wiped out and a little old lady who put her 50
I saw Eddie Large in a Bradford casino in 81. He was with Norman Collier,they'd been appearing in Aladdin at the Bradford Alhambra, with Syd of course. Very funny man, out of character. After changing cash for chips 3 times, he threw his 4th deposit on the table and said there goes this week's rent. After finally losing all his deposits, he started to leave the table, and muttered, I can't believe my luck. If I was in a marching band I'd be the pianist, a brilliant line I use now and then.
I saw Eddie Large in a Bradford casino in 81. He was with Norman Collier,they'd been appearing in Aladdin at the Bradford Alhambra, with Syd of course. Very funny man, out of character. After changing cash for chips 3 times, he threw his 4th deposi
Don't know what they're like these days, but when I worked at SIS it would have been easy to rig or pre-record a draw and have it right off, especially if the rampant homosexualist who used to be the invigilator had his eye on you.
Don't know what they're like these days, but when I worked at SIS it would have been easy to rig or pre-record a draw and have it right off, especially if the rampant homosexualist who used to be the invigilator had his eye on you.
kenny, the event is a "number" coming up 6 times in a row not specifically "17" coming up 6 times in a row. Slippy Blue would still have made the observation if 5 or 32 had come up 6 times in a row. So the first roll is not counted in calculating the probability.
00 0 1-36 are 38 numbers so the odds are 38^5 not 37^5.
kenny, the event is a "number" coming up 6 times in a row not specifically "17" coming up 6 times in a row. Slippy Blue would still have made the observation if 5 or 32 had come up 6 times in a row. So the first roll is not counted in calculating t
An invigilator from a big accounting firm can hardly be very motivated. He was thinking that at this point in his career he'd be taking large backhanders from the likes of Enron and he is actually the equivalent of a circus clown.
An invigilator from a big accounting firm can hardly be very motivated. He was thinking that at this point in his career he'd be taking large backhanders from the likes of Enron and he is actually the equivalent of a circus clown.
your answer is "correct" (tho you are still wrong about the 2 zeroes) for someone asking what are the odds of specifically 17 coming up 6 times in a row, but that isn't the phenomenon observed. The phenomenon observed is a number repeating 5 times.
In the OP we aren't considering the odds of 23, 29 etc coming up and then 27 29 etc coming up after, just the odds of the second set.
The first occurrence is ignored just like in Slippy's observation.
your answer is "correct" (tho you are still wrong about the 2 zeroes) for someone asking what are the odds of specifically 17 coming up 6 times in a row, but that isn't the phenomenon observed. The phenomenon observed is a number repeating 5 times.I
For some strange reason on 49s website, they're only showing 'previous results' up to march 17. Its never before not been updated to the previous day's results. You cant help feeling they're too embarassed to post the results for march 18, and of course they cant then post subsequent results cos there would be a glaring gap. Spooky beyond words imo ....
For some strange reason on 49s website, they're only showing 'previous results' up to march 17. Its never before not been updated to the previous day's results. You cant help feeling they're too embarassed to post the results for march 18, and of cou
when the girl is on there are no balls in the drum
when draw takes place all looking bit iffy no adjudicator in sight
glitch on 18th produced that result
FIX
i think they were doing a cheaper virtual gamewhen the girl is on there are no balls in the drumwhen draw takes place all looking bit iffy no adjudicator in sightglitch on 18th produced that resultFIX