I haven't got any workings with mine, it was a complete guess as I'm terrible at maths. I just felt bad for you that nobody had answered and wanted to jog things on a bit.
I haven't got any workings with mine, it was a complete guess as I'm terrible at maths. I just felt bad for you that nobody had answered and wanted to jog things on a bit.
BTW I'm an accountant, so if you want a different answer, just let me know (it'll cost though)
Here it is ...5r+1=a(m+r)5r+1=am+ar5r-ar=am-1r(5-a)=am-1r=(am-1)/(5-a)BTW I'm an accountant, so if you want a different answer, just let me know (it'll cost though)
AB is 4cm CD is k cm longer than 4cm BC is square root of 3 cm
The area of trapezium is 5 multiply square root 6 cm squared
calculate k in form a root b - c where a b amd c positive intergers
ABCD is a trapeziumAB is 4cmCD is k cm longer than 4cmBC is square root of 3 cmThe area of trapezium is 5 multiply square root 6 cm squaredcalculate k in form a root b - c where a b amd c positive intergers
BTW I'm an accountant, so if you want a different answer, just let me know (it'll cost though)
Haven't done quadratic equations in 30 years. Had to Google how to do them
BTW I'm an accountant, so if you want a different answer, just let me know (it'll cost though) Haven't done quadratic equations in 30 years. Had to Google how to do them
A ______4_____ B /l l / l 1 / l l root 3 / l 1 /____l__________l k D X C
Area ABCD given as (5 x root6) squared
Area ABCX = 4 x root3
Area AXD = (5 x root6 squared) - (4 x root3)
Area AXD = (k x root3)/2
therefore (k x root 3)2 = (5 x root 6 squared) - (4 x root3)
so you can solve the value of k by just doing the above calc.
(I reckon)
If you want me to show it as an expression though, it'll cost (I'm an accountant and former management consultant so can't do it all for free)
Trapezium looks like A ______4_____ B /l l / l 1 / l l root 3 / l 1 /____l__________l k D X CArea ABCD given as (5 x root6) squaredArea ABCX = 4 x root3Area AXD = (5