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14190/1 ish
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blackestnight I think you have to multiply your answer by 6C3 (which is 20)
709.5/1 |
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Thanks. So the 20 is (6*5*4)/(1*2*3).
And the 14091/1 is….? |
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I did trebles from 45 numbers, I thought it seemed a little high.
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I would guess that trebles from 45 numbers would be the correct route.
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3 from 45 is 14190 (45 x 44 x 43 / 3 x 2 x 1 )
then there are 6 numbers drawn so you get 20 chances to get 3 from 6 (6 x 5 x 4 / 3 x 2 x 1 ) (45 x 44 x 43 / 3 x 2 x 1 ) --------------------------- = 709.5 (6 x 5 x 4 / 3 x 2 x 1 ) |
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(45 x 44 x 43 / 3 x 2 x 1 )
--------------------------------------- = 709.5 (6 x 5 x 4 / 3 x 2 x 1 ) |
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Thanks!
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Donny Osmond has the correct answer.
Some on here not as clever as they thought they were. |
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I'm definitely not!
I thought, at first, that it was just a matter of 'how many trebles'? It took me a while to understand WHY the number of balls drawn out should have any effect on things. After all, if your three balls aren't drawn out...you don't win. But, of course, it's not as cut and dried as that. Fortunately.I prefer to bet in singles because the 'double' is a bet that was created for those who aren't content with just ONE loser! |