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2 people have a combined score of 638 with 1 scoring 32% more than the other, what did they both score as individuals?
Worked it out using trial and error, took 3 guesses, but there must be a formula to follow without using trial and error??
Worked it out using trial and error, took 3 guesses, but there must be a formula to follow without using trial and error??
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638/232*100 = 1 score
638-above = 2 score |
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1=275
2=363 total=638 |
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Where do you get the 232 bit from that figure was nt supplied although doing that does give the right answer.
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b = 1.32a
a + b = 638 b = 638-a 638-a = 1.32a 638 = 1.32a + a 638 = 2.32a a = 638/2.32 = 275 b - 638 - 275 = 363 a = 275 b = 363 |
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b = 638 - 275 = 363
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1 score = 100%
2 score = 132% Total = 232 |
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Ah right, thanks gin
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