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Maths Q
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SPYKES
Date Joined:
12 Oct 03
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03 Oct 14 15:11
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SPYKES's blog
2 people have a combined score of 638 with 1 scoring 32% more than the other, what did they both score as individuals?
Worked it out using trial and error, took 3 guesses, but there must be a formula to follow without using trial and error??
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Gin
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October 3, 2014 3:18 PM BST
638/232*100 = 1 score
638-above = 2 score
638/232*100 = 1 score638-above = 2 score
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Gin
•
October 3, 2014 3:19 PM BST
1=275
2=363
total=638
1=2752=363total=638
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SPYKES
•
October 3, 2014 3:20 PM BST
Where do you get the 232 bit from that figure was nt supplied although doing that does give the right answer.
Where do you get the 232 bit from that figure was nt supplied although doing that does give the right answer.
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Stow_judge
•
October 3, 2014 3:21 PM BST
b = 1.32a
a + b = 638
b = 638-a
638-a = 1.32a
638 = 1.32a + a
638 = 2.32a
a = 638/2.32 = 275
b - 638 - 275 = 363
a = 275
b = 363
b = 1.32aa + b = 638b = 638-a638-a = 1.32a638 = 1.32a + a638 = 2.32aa = 638/2.32 = 275b - 638 - 275 = 363a = 275b = 363
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Stow_judge
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October 3, 2014 3:22 PM BST
b
=
638 - 275 = 363
b = 638 - 275 = 363
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Gin
•
October 3, 2014 3:23 PM BST
1 score = 100%
2 score = 132%
Total = 232
1 score = 100%2 score = 132%Total = 232
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SPYKES
•
October 3, 2014 3:25 PM BST
Ah right, thanks gin
Ah right, thanks gin
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