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Imagine you are in a rectangular room 3meters wide, 5 meters long and 3 meters high. At 2 opposing ends of the room therefore is a square wall 3 meters wide and 3 meters high. On the vertical centre line one of these square walls is a black dot 1 meter from the floor. On the vertical centre line of the opposing square wall is a black dot 1 meter from the ceiling i.e. 2 meters from the floor.
You have a marker pen and your task is to draw a single continuous line connecting both the dots. You can draw on any of the walls plus the floor and the ceiling if you wish. Assume all walls are perfectly vertical, and the floor and ceiling perfectly horizontal
What is the shortest line you can draw to join the 2 dots?
You have a marker pen and your task is to draw a single continuous line connecting both the dots. You can draw on any of the walls plus the floor and the ceiling if you wish. Assume all walls are perfectly vertical, and the floor and ceiling perfectly horizontal
What is the shortest line you can draw to join the 2 dots?
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45 meters
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ffs, now the missus is in a foul mood because of all the black dots painted in her walls.
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8 m? (this is probably wrong because its the obvious answer)
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10 metres
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sorry 8 metres
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Oh bugger. Sorry, sorry, sorry.
The room is 10 meters long not 5. |
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the answer is 13m then
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Kevin1958 21 Dec 13:08
You can draw on any of the walls plus the floor and the ceiling if you wish. Told her you said it was ok, she's still not happy though. |
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Imagine you are in a rectangular room 3meters wide, 10 meters long and 3 meters high. At 2 opposing ends of the room therefore is a square wall 3 meters wide and 3 meters high. On the vertical centre line one of these square walls is a black dot 1 meter from the floor. On the vertical centre line of the opposing square wall is a black dot 1 meter from the ceiling i.e. 2 meters from the floor.
You have a marker pen and your task is to draw a single continuous line connecting both the dots. You can draw on any of the walls plus the floor and the ceiling if you wish. Assume all walls are perfectly vertical, and the floor and ceiling perfectly horizontal What is the shortest line you can draw to join the 2 dots? |
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13 metres then
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No 13 is incorrect.
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How high is the door?
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Dont worry about the door Harry.
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(10^2 +1^2)^(1/2)
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where is this room? does it have windows?
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It doesn't matter where the room is. It may have windows but thats nothing to do with the question or the solution.
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sorry (13^2 + 1^2) ^(1/2)= 13 and a bit. that is further than the line down the centre of the room. How can 13 not be right?
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evski. Wrong.
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13 is the answer, and it's the answer whether you draw along the walls OR the ceiling OR the floor.
Ipso facto imo. |
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13 is not the answer. a priori: from the former. If you think something a priori, you are conceiving it before seeing the facts.
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That was for 3753. lol
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13 isn't the answer i don't think.
i think it would be shorter if you went sideways from the dot, and then at a slight angle along the wall (rather than along the floor or ceiling). |
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no, if you went at a slight angle the answer would be 170^1/2 which is a bit further than 13m.
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7M
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Gene. The room is 10 meters long.
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so are you saying the answer is less than 13m kevin?
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Kev
The room is 5 metres long. 7M is wrong I have just realised. |
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Yes. The answer is less than 13 meters.
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Gene. The room is 10 meters long.
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I'm making the room now to see where I'm going wrong.
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Sorry Kev,I didn't realise you'd increased the size of your room after asking the original question based on the room being 5 metres long.Sorry.
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evski. That's what I did.
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No worries Gene. It was my mistake. It can be done in less than 13 meters though.
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my room disagrees. Please just put me out of my misery. How can it be done?
I just can't see how you can beat a straight line. |
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evski. If you have drawn the room, you can't be too far away from the solution.
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Obviously, you cant beat a straight line.
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is it 10.05 metres?
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Which wall has the door?
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It couldn't be anywhere near as short as 10.05 metres, the room is 10 metres long.
The door is not important for the solution. |