Chit Chat
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1. What is special about 1/7th ?
2. A farmer has a square field. There is a bull somewhere in the field. The bull is secured by tight ropes to three of the corner posts. The ropes are 30m, 40m and 50m long. What is the area of the field ?
3. You are Captain Jack Sparrow and about to distribute your plunder to your scurvy crew. If more than half of them object to your distribution they will vote to make you walk the plank and keep all the treasure themselves. How can you maximise your own health, safety and take ?
4. It takes two politicians eight days to claim all the expenses. One is Labour and one is Conservative. The Labour one would take 12 days to claim them all on her own. How many days would the Conservative take to claim them all on his own?
2. A farmer has a square field. There is a bull somewhere in the field. The bull is secured by tight ropes to three of the corner posts. The ropes are 30m, 40m and 50m long. What is the area of the field ?
3. You are Captain Jack Sparrow and about to distribute your plunder to your scurvy crew. If more than half of them object to your distribution they will vote to make you walk the plank and keep all the treasure themselves. How can you maximise your own health, safety and take ?
4. It takes two politicians eight days to claim all the expenses. One is Labour and one is Conservative. The Labour one would take 12 days to claim them all on her own. How many days would the Conservative take to claim them all on his own?
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Replies: 101
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They don't look like proper puzzles to me. I'd suspect someone of playing a rather lame joke on you.
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part of an xmas quiz, I have got the other ones. I am sure the farmer one is quite easy I just can't remember my trigonometry.
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I don't think so.
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1. Gold
2. 60m squared 3.Baked Beans 4. Not on a tuesday |
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The cow one is probably based on 3:4:5 right-angled triangles. HTH.
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2. 3200
4. 20 maybe |
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lets say expenses =100
c = amount claimedper day by tory l = amount claimed per day by labour 8c + 8l = 100 l = 12.5 - c but 12l = 100 = 150 - 12c 12c= 50, therefore c = 4 and one sixth 100 divided by 4 and one sixth = 24 days. I think?? |
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1 = Terry Hall
2 = the field's in Norfolk 3 = Kill them all 4 = sorry don't know that one |
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can't even work out how to draw the field one in CAD
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field one is probably 3200 but there are many possible combinations.
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infact 3200 is wrong
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3200 works - square with 56.56m sides
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3600m^2 is the correct answer
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3600 is correct
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the 30m and 50m at opposite corners, 40m at other corner.
Haven't used trigonometry for years... Hyp is 80m, angle 45. opp = sin 45*80 = 56.56 squared = 3200? No? |
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arses, how you get 3600?
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as in, why is it 60m squared?
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A bulls neck is about 1 metre wide and this should be taken into consideration
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that's what I got first time but I think there is a second solution
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it isn't 3600 imo
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I just drew it out and now I'm trying to prove it. Gimme a minute.
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I worked it out as per Jimbo
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ok, if the field is 60m each side, then the hypetnuse must be
square root of 60*60 + 60*60 dunno how you do square root on windows calc... |
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but its more than 90, then I can't see how the answer is 3600.
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what jimbo and jbha says does seem to work. but you were assuming that the 3 and the 5 are in a straight line. giving a hypotenuse of 8. This is correct, though only by chance. I think.
3600 defo wrong. have drawn both out on AutoCAD and 3200 is defo right |
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Don't think you can. I'm fairly sure that there is another solution and I tought I could use the sine rule (non right andgled triangle.) but the I realise that I don't have any of the angles in my diagram so I cannot prove it. The easiest answer is of course 3200. I'm just annoyed that I can't work out another solution which I'm fairly sure exists.
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If the rope is in the corners, and tight, then it must have 50m one end, and either 30m the other (creating a right angle triangle) or 50m one end, 40m the other, and 30 m pulling it to a corner. Therefor creating an isosles triangle.. will work out that solution now.
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This creates a triangle of length 40m * 30m * xm
Can't work out x as I dont have a feckin calcualtor! |
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once you know x, square it and see if is 56 or 60.
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I think the 3200 answer is right, but the derivation flawed.
i haven't seen any convincing proof yet. |
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Question 2 is based on a right angled triangle (as pointed out above)
3,4,5 RA triangle is quite common 3 squared + 4 sqaured = 5 squared 9+16 = 25 - thus we know it is a right angled triangle in this case 30 squared + 40 squared = 50 squared given that the 30 and 40 side are at right angles we can use the area of a triangle formula which is 1/2 base x height 1/2 x 40 = 20 x 30 = 600 metres squared |
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how would you work it out Jimbo? I can't do it without at least one angle and I can't seem to find a way to calculate an angle.
Haven't done any trig for many years. |
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btw it looks as though one or two of you have missed the point of the question
2. A farmer has a square field. There is a bull somewhere in the field. The bull is secured by tight ropes to three of the corner posts. The ropes are 30m, 40m and 50m long. What is the area of the field ? The fact that it is a square field is irrelevant |
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I thank you ;)
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FFT: none of that makes sense to me. the 30,40 and 50 are not forming a triangle
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well done FFT.
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only 3 of the 4 corner posts are in use, so therefore a triangle has been created
the 4th corner post is doing the square root of feck all |
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i agree with pos, the 30 40 50 aren't sides of a triangle, they are distances from a single point
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the 30 and the 50 combine, the 40 meets the 2 - they dont form a triangle
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