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09 Nov 09
12:58
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Date Joined:
30 Mar 07
Am here a work and teying to resolve following question?
You have 12 numbers one to twelve. What are the odds of predicting correctly first six numbes drawn from hat? And equation to work it out?
You have 12 numbers one to twelve. What are the odds of predicting correctly first six numbes drawn from hat? And equation to work it out?
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or 1/12 x 1/11 x 1/10 x 1/9 x 1/8 x 1/7 if you are only picking 1 number before each drawing , than 6 at the start
1st reply should read 6/12 x 5/11 x 4/10 x 3/9 x 2/8 x 1/7 but i think my other post is what you are after
i agree with oval man my other work mate does not
Ken has given my answer in an easier form to understand
Do you have to get the correct order or just which 6 of the 12 will be first ones out?
no real order. just six numbers tomatch with your six numbers
ffs, with all the figures people on here you would think someone would know it.
Ah, in that case it's (1/2 x 5/11 x 2/5 x 1/3 x 1/7) = 1/161
Well I've just drawn 231 times and it only happened once.
If order doesn't matter I'd be inclined to think that as odds of any individual number being drawn out in first 6 is evens, its a 6 runner acca all at Evens, ie 63/1. Can't be that simple tho, can it?
n!/ r! (n-r)!
where: n is the number of balls
r is the number of balls to be picked
so the lottery would be calculated like this:
49!/ 6! (49-6)!
if your question is supposed to work like a lottery the answer is :
12!/ 6!6!
where: n is the number of balls
r is the number of balls to be picked
so the lottery would be calculated like this:
49!/ 6! (49-6)!
if your question is supposed to work like a lottery the answer is :
12!/ 6!6!
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