Cheltenham Festival
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Cheltenham, Gold Cup Distance, Good to Soft
In lengths, how far would you be behind the winner if you finished 9 seconds adrift
many thanks in advance
In lengths, how far would you be behind the winner if you finished 9 seconds adrift
many thanks in advance
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Over the gold cip trip I'd have guessed at just over half that distance.
OK - the Gold Cup is run over 5300 m = 17388 feet.
In 2008 on G-S (as per the question) it was won by Denman in 6 m 48 s = 408 s.
= 42.6 feet per second (for the winner).
Therefore 9 s (per the question) = 383.5 feet = 48 lengths (assuming per standard 8 feet per length).
The horse concerned would obviously have run slower than the winner and the calculation also assumes the race is run at an even rate (i.e. the horse finishes the race at its average speed) - but the approximation is ok.
In 2008 on G-S (as per the question) it was won by Denman in 6 m 48 s = 408 s.
= 42.6 feet per second (for the winner).
Therefore 9 s (per the question) = 383.5 feet = 48 lengths (assuming per standard 8 feet per length).
The horse concerned would obviously have run slower than the winner and the calculation also assumes the race is run at an even rate (i.e. the horse finishes the race at its average speed) - but the approximation is ok.
I should add that in british racing the winning margin in lengths is not actually a function of distance but a function of time. For a jumps race on G-S it's a standard 4.5 l per second, so 9 s is defined as a 40.5 l margin.
This ranges from 4 l/s to 6 l/s depending on the surface, race type and going.
This ranges from 4 l/s to 6 l/s depending on the surface, race type and going.
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