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							<channel><title>New Posts For Thread: quick odds question</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question</link><description>Assuming the odds for the draw in each game was 25/1 - What would be the odds on a team in the 6 nations drawing twice in one tournament?I make it about 75/1 but am not sure.........</description><item><title>Using binomial probabilities (n=5, p=1/26), the probability of getting exactly 2 draws is 0.013150834 or almost exactly 75/1. The probability of 2 draws or more is 0.013687 or 72/1.</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=548018761#548018761</link><description>Using binomial probabilities (n=5, p=1/26), the probability of getting exactly 2 draws is 0.013150834 or almost exactly 75/1. The probability of 2 draws or more is 0.013687 or 72/1.</description><pubDate>Mon, 07 Mar 2016 09:59:34 -0600</pubDate></item><item><title>333/5 is 66.6/1 which is what I said earlier.</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=548018547#548018547</link><description>333/5 is 66.6/1 which is what I said earlier.</description><pubDate>Mon, 07 Mar 2016 09:10:25 -0600</pubDate></item><item><title>Sorry 333/5 not 288/5 .</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=548017625#548017625</link><description>Sorry 333/5 not 288/5 .</description><pubDate>Mon, 07 Mar 2016 05:16:29 -0600</pubDate></item><item><title>12 minutes to log in today!Clearly there will be 0,1,2,3,4 or 5 draws in your 5 selected matches. By the laws of probability;P(0)+P(1)+P(2)+P(3)+P(4)+P(5)=1then P(2)+P(3)+P(4)+P(5)= 1 - {P(0)+P(1)}then using Pascal/BinomialP(0)= 1*(25/26)^5P(1)= 5*(1</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=548017443#548017443</link><description>12 minutes to log in today!Clearly there will be 0,1,2,3,4 or 5 draws in your 5 selected matches. By the laws of probability;P(0)+P(1)+P(2)+P(3)+P(4)+P(5)=1then P(2)+P(3)+P(4)+P(5)= 1 - {P(0)+P(1)}then using Pascal/BinomialP(0)= 1*(25/26)^5P(1)= 5*(1</description><pubDate>Mon, 07 Mar 2016 04:21:54 -0600</pubDate></item><item><title>For 2 or more there are a few more calculations and my trusty Casio is displaying "low battery" so no can do.</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=548013471#548013471</link><description>For 2 or more there are a few more calculations and my trusty Casio is displaying "low battery" so no can do.</description><pubDate>Sun, 06 Mar 2016 14:08:38 -0600</pubDate></item><item><title>If you mean twice and no more than twice then your answer is , I think, as follows. Assuming independence.10* (1/26)^2*(25/26)^3 which comes to around 76/1.I will give it some more thought though.</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=548013429#548013429</link><description>If you mean twice and no more than twice then your answer is , I think, as follows. Assuming independence.10* (1/26)^2*(25/26)^3 which comes to around 76/1.I will give it some more thought though.</description><pubDate>Sun, 06 Mar 2016 14:06:00 -0600</pubDate></item><item><title>Thanks pump.</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=547921679#547921679</link><description>Thanks pump.</description><pubDate>Fri, 26 Feb 2016 02:43:14 -0600</pubDate></item><item><title>5 matches played by each team any two from 5 = 10 so at 25/1 that's 26x26 divided by 10 = 67.6 that's 66.6/1That obviously is taking one specific team to draw twice, if the bet was any of the six teams drawing twice then that becomes more problematic</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=547912971#547912971</link><description>5 matches played by each team any two from 5 = 10 so at 25/1 that's 26x26 divided by 10 = 67.6 that's 66.6/1That obviously is taking one specific team to draw twice, if the bet was any of the six teams drawing twice then that becomes more problematic</description><pubDate>Thu, 25 Feb 2016 05:46:35 -0600</pubDate></item><item><title>Would aybody care to share how this is worked out? Thanks.</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=547912081#547912081</link><description>Would aybody care to share how this is worked out? Thanks.</description><pubDate>Thu, 25 Feb 2016 02:54:42 -0600</pubDate></item><item><title>nearly 67/1</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30657867/quick-odds-question?post_id=547909157#547909157</link><description>nearly 67/1</description><pubDate>Wed, 24 Feb 2016 15:29:52 -0600</pubDate></item></channel></rss>
