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							<channel><title>New Posts For Thread: Maths Help</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30332653/maths-help</link><description>If A, B &amp; C have an equal chance of winning what is the likelihood of A/B/C winning 5x consec and what is the likelihood of AB/AC/BC winning 5x consec...Thanks in advance!</description><item><title>Thanks.</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30332653/maths-help?post_id=541053219#541053219</link><description>Thanks.</description><pubDate>Thu, 21 Aug 2014 11:09:29 -0500</pubDate></item><item><title>That works.</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30332653/maths-help?post_id=541052699#541052699</link><description>That works.</description><pubDate>Thu, 21 Aug 2014 10:41:20 -0500</pubDate></item><item><title>By AB I mean dutching A&amp;B so if I was to use the same logic you used for A, B &amp; C alone would I be correct in assuming that the percentage of (2/3)^5 = 0.13116 or 13.11%</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30332653/maths-help?post_id=541052091#541052091</link><description>By AB I mean dutching A&amp;B so if I was to use the same logic you used for A, B &amp; C alone would I be correct in assuming that the percentage of (2/3)^5 = 0.13116 or 13.11%</description><pubDate>Thu, 21 Aug 2014 10:12:51 -0500</pubDate></item><item><title>IF A, B &amp; C have an equal chance of winning (and there are no other possible outcome) the chance of any of them winning once is 1/3, so the chance of any winning 5 times consecutively is (1/3)^5 = 0.0041 or 0.41%.No idea what you mean by "AB/AC/BC wi</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30332653/maths-help?post_id=541051627#541051627</link><description>IF A, B &amp; C have an equal chance of winning (and there are no other possible outcome) the chance of any of them winning once is 1/3, so the chance of any winning 5 times consecutively is (1/3)^5 = 0.0041 or 0.41%.No idea what you mean by "AB/AC/BC wi</description><pubDate>Thu, 21 Aug 2014 09:50:47 -0500</pubDate></item><item><title>If A, B &amp; C have an equal chance of winning what is the likelihood of A/B/C winning 5x consec and what is the likelihood of AB/AC/BC winning 5x consec...Thanks in advance!</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/30332653/maths-help?post_id=541049685#541049685</link><description>If A, B &amp; C have an equal chance of winning what is the likelihood of A/B/C winning 5x consec and what is the likelihood of AB/AC/BC winning 5x consec...Thanks in advance!</description><pubDate>Thu, 21 Aug 2014 07:59:02 -0500</pubDate></item></channel></rss>
