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							<channel><title>New Posts For Thread: Maths problem</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem</link><description>A bag has 2 red balls and 2 black balls. If 2 balls are picked at random the chances are 66.7% that the balls are different colours. My 10yo son was convinced it was 50/50 so I challenged him to a free bet, takind two red and two silver baubles off</description><item><title>1. did your maths teacher never tell you to spend an insanely excessive amount of time reading the question before you picked up your pen?2. i'm going to lay you 10/1 about two blue balls coming out, because i think you're special. how much would you</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428810#419428810</link><description>1. did your maths teacher never tell you to spend an insanely excessive amount of time reading the question before you picked up your pen?2. i'm going to lay you 10/1 about two blue balls coming out, because i think you're special. how much would you</description><pubDate>Thu, 17 Dec 2009 13:16:59 -0600</pubDate></item><item><title>the chances of two reds being pulled out is ....16.66.....5/1thge cnances of two blues being pulled out....16.66......5/1the chances of two odds balls being poulled out is.......66.66....1/2the chances of any matched coloured balls being pulled out i</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428654#419428654</link><description>the chances of two reds being pulled out is ....16.66.....5/1thge cnances of two blues being pulled out....16.66......5/1the chances of two odds balls being poulled out is.......66.66....1/2the chances of any matched coloured balls being pulled out i</description><pubDate>Thu, 17 Dec 2009 03:39:35 -0600</pubDate></item><item><title>same solution basicallywhen W = 2B you can rewrite the denominator as difference of two squares, then simplify to get:R_B = 1 / ( 1 + ( q / p ) ^ B )q/p = 1/2 and B = 5 gives:R_5 = 1 / (1 + (1/2)^5) = 32/33 = 0.03030303...</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428602#419428602</link><description>same solution basicallywhen W = 2B you can rewrite the denominator as difference of two squares, then simplify to get:R_B = 1 / ( 1 + ( q / p ) ^ B )q/p = 1/2 and B = 5 gives:R_5 = 1 / (1 + (1/2)^5) = 32/33 = 0.03030303...</description><pubDate>Wed, 16 Dec 2009 10:31:14 -0600</pubDate></item><item><title>I'm not familiar with any high falutin' maths stuff, so apologies for the kitchen sink approach!Contrarian, I have the equations as:(where P(91) = prob of winning from 9-1 ahead)P(91)=2/3 + 1/3 P(82)P(82)=2/3 P(91)+1/3 P(73) ...P(28)=2/3 P(37) + 1/3</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428598#419428598</link><description>I'm not familiar with any high falutin' maths stuff, so apologies for the kitchen sink approach!Contrarian, I have the equations as:(where P(91) = prob of winning from 9-1 ahead)P(91)=2/3 + 1/3 P(82)P(82)=2/3 P(91)+1/3 P(73) ...P(28)=2/3 P(37) + 1/3</description><pubDate>Wed, 16 Dec 2009 04:18:13 -0600</pubDate></item><item><title>Apologies to Eldrick if this is just a long-winded version of his method, but you could do this:Get a series of 9 equations relating the probabilities of winning from the various scores. Eg:P(win from 9-1) = 1/3 + (2/3 * P(win from 8-2)P(win from 8-2</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428594#419428594</link><description>Apologies to Eldrick if this is just a long-winded version of his method, but you could do this:Get a series of 9 equations relating the probabilities of winning from the various scores. Eg:P(win from 9-1) = 1/3 + (2/3 * P(win from 8-2)P(win from 8-2</description><pubDate>Tue, 15 Dec 2009 16:01:58 -0600</pubDate></item><item><title>I just played with two jacks and two queens from a deck of cards. 5 points each at start same - different5-54-63-72-83-74-63-72-81-92-81-90-10</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428590#419428590</link><description>I just played with two jacks and two queens from a deck of cards. 5 points each at start same - different5-54-63-72-83-74-63-72-81-92-81-90-10</description><pubDate>Tue, 15 Dec 2009 16:00:21 -0600</pubDate></item><item><title>I ~concur with Mr Bushy0.030303030303030303using a spreadsheet solution</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428586#419428586</link><description>I ~concur with Mr Bushy0.030303030303030303using a spreadsheet solution</description><pubDate>Tue, 15 Dec 2009 15:52:04 -0600</pubDate></item><item><title>Write total bank as B, set constant stake at 1, bet pays even money so at each step bank moves up 1 with prob p, down 1 with prob (1-p)=qSay you stop after your bank reaches some amount WNow let R_B = Pr(Funds reach W before they reach 0, given curre</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428582#419428582</link><description>Write total bank as B, set constant stake at 1, bet pays even money so at each step bank moves up 1 with prob p, down 1 with prob (1-p)=qSay you stop after your bank reaches some amount WNow let R_B = Pr(Funds reach W before they reach 0, given curre</description><pubDate>Tue, 15 Dec 2009 15:33:50 -0600</pubDate></item><item><title>bushy you sound like mr logic out of the viz</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428578#419428578</link><description>bushy you sound like mr logic out of the viz</description><pubDate>Tue, 15 Dec 2009 13:12:36 -0600</pubDate></item><item><title>cheers bushy and others.</title><link>https://community.betfair.com/general_betting/go/thread/view/94082/23481790/maths-problem?post_id=419428574#419428574</link><description>cheers bushy and others.</description><pubDate>Tue, 15 Dec 2009 13:10:40 -0600</pubDate></item></channel></rss>
